2×3 = 6m2

hustota = 1500 kg/m3 thermal_capacity = 800 J/kg.m3.C

Ak by sme chceli ohriat o 100 stupnov
= 6 x 1500 x 800 x 100 = 720 000 000 J = 720 000 KJ = 200 kWh (200×0.15 EUR = 30EUR)

Ak by som mal 4 panely s vykonom 200W a slnko by svietilo 4 hodiny denne

to by bolo 800wh x 4 denne = 2400wh = 2.4kwh = 2.4 x 3600 = 8 640 KJ. Takyto pieskovy kvader by som za 1 den ohrial o 6 x 1500 x 800 x D = 8 640 KJ z toho D = (6 x 1500 x 800 / 8640000) a to je 0.83 stupna Celzia, kde D je teplotny rozdiel.